Sometimes we love our city so much that we don't want to leave—even for a vacation. The next best thing? A sweet staycation in Austin. Well, you're in luck: We're offering one winner the chance to enjoy a night at the W Austin, along with a $50 gift certificate to the hotel's Trace restaurant. And if you want to continue the night after dinner? We're also offering a $50 gift certificate to The Roosevelt Room, where you can sip on swanky cocktails before retiring to your hotel room. Enter below—what have you got to lose?
Austin Staycation Giveaway Official Rules
CONTEST RULES: One entry per person. These competitions are open to any U.S. resident (unless otherwise stated) except employees of Time Out and sponsoring organizations, their agents or anyone directly connected to these promotions. No purchase required for this promotion. Contest valid 4/10/17 through 5/08/17 at 11:59:59pm EST. Winners must be 21 years of age or older unless otherwise stated. Prizes are as described above; no cash alternatives will be given. Prizes may not be sold, traded, transferred or refunded. Any and all federal, state and local taxes are the responsibility of the winner. If for any reason winners are unable to use prizes within the time specified, the participating organizations are not responsible for providing replacement prizes. No make goods will be given in the event of a canceled or rescheduled event. Approximate retail value: $500.
DISCLAIMER AND WAIVER: Time Out does not endorse or make any representation about the prize or quality of the services that are part of the prize. By participating in this contest, entrants agree to receive promotional emails from Time Out and waive any claims against Time Out arising out of use of the prize and related services. The odds of winning are relative to the number of correct, eligible entries received; winners will be drawn at random from this pool.